7(1.02^4x+1)=10

Simple and best practice solution for 7(1.02^4x+1)=10 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 7(1.02^4x+1)=10 equation: 



7(1.02^4x+1)=10

We move all terms to the left:

7(1.02^4x+1)-(10)=0

We multiply parentheses

7x+7-10=0

We add all the numbers together, and all the variables

7x-3=0

We move all terms containing x to the left, all other terms to the right

7x=3

x=3/7

x=3/7

See similar equations:

| 4(3x-4)=31-4(x-3) | | 6x-8=2-4x | | 2(4x-8)=29-4(x+1) | | 2x+41=51 | | 2x-5+44+111=180 | | -2+4x-10x=4 | | 8x=6x+44 | | 4(y+5)–14=10 | | 5+.83x=x/3-1 | | x-4-4x=2x-8+8x | | 2401^r-5=7^3(r-2 | | 6+7p=10+6p | | H(x)=0.6+1.5 | | 9x-6-3x=-5x-18+x | | 2-3/8x=14 | | 20=0.40x | | 62+78={2x-4) | | x+0.16x=65 | | 3x²+18x=48 | | 5b+1=1+5b | | 7a−2=16 | | 30=26-a/5 | | -3y+21=3(y+1) | | 3x-18=87 | | 5a-4a=a-4 | | -48-x=393 | | 57=-x+22 | | 3(x-3)+2(x+1)=-14 | | √2b+7=3 | | 3(n+5)=7(n-3) | | 95=3x-4 | | q^2-14q+5=0 |

Equations solver categories